How much JEE score is required for CSE at IIT Roorkee?

By AKSHAT | 19 February 2024

IIT Roorkee is Asia's oldest technical university. It was established in 1847 as Thomason College of Civil Engineering and later converted into an IIT by the Government of India. 

For Admission in IIT Roorkee, the candidate needs to focus more on JEE Advanced Rank rather than score.

Also, candidate must have to secure at least 75% marks (65% for SC/ST/PwD) in Class 12th

Final Round Closing Rank of CSE for GEN Category is; 412 Rank (2023) 413 Rank (2022) 416 Rank (2021)

Get Direct Admission in Top Engineering Institutes in India through Management Quota.

Final Round Closing Rank of CSE for EWS Category is; 70 Rank (2023) 75 Rank (2022) 80 Rank (2021)

Final Round Closing Rank of CSE for OBC Category is; 196 Rank (2023) 213 Rank (2022) 196 Rank (2021)

Final Round Closing Rank of CSE for SC Category is; 109 Rank (2023) 123 Rank (2022) 111 Rank (2021)

Final Round Closing Rank of CSE for ST Category is; 61 Rank (2023) 60 Rank (2022) 62 Rank (2021)